Book, Paragraph

 1   I,  7|       through it quickly in a line. Now if this fire were to
 2  II,  6|       Aparctias, from K. (The line IK nearly coincides with
 3  II,  8|     like a long very straight line. This is because the wind
 4 III,  1|       advancing in a straight line: at the same time it is
 5 III,  1|      is blowing in a straight line, and whirls round by its
 6 III,  3|        See diagram.)~Draw the line AEB. Then the triangles
 7 III,  3|   point E. So if you draw the line it will be a circle and
 8 III,  3|      the cloud from which the line of sight is reflected to
 9 III,  5|    planes passing through the line HK and determined by the
10 III,  5|    the points H and K and the line KH are given, the line MH
11 III,  5|    the line KH are given, the line MH will be given too; consequently
12 III,  5| consequently the ratio of the line MH to the line MK will be
13 III,  5|   ratio of the line MH to the line MK will be given too. So
14 III,  5|  circumference but MN.~Draw a line DB outside of the figure
15 III,  5|       than B. Then add to B a line Z such that B+Z:D=D:B. Then
16 III,  5|      D=D:B. Then make another line having the same ratio to
17 III,  5|     be in the same ratio to a line indifferently lesser or
18 III,  5| greater than IM, and let this line be IP. Then HK and KI and
19 III,  5| cannot bear that ratio to any line either lesser or greater
20 III,  5|       the sun are on the same line. But since KH lies above
21 III,  5|    centre will be at O on the line KI below the plane of the
22 III,  6|      of the sky, for then the line of vision is not close to