Book, Paragraph

 1  II,  6|      sets at the equinox and B, the point opposite, the
 2  II,  6|    is Apeliotes blowing from B the point where the sun
 3 III,  3|     the point A to the point B and forms an angle. Let
 4 III,  3|     AD be equal and those at B, GB, ZB, DB equal too. (
 5 III,  3| circle and E its centre. Now B is the sun, A the eye, and
 6 III,  4|      the same principle. Let B be the outer rainbow, A
 7 III,  5|      and divide it so that D:B=MH:MK. But MH is greater
 8 III,  5|  Therefore D is greater than B. Then add to B a line Z
 9 III,  5|  greater than B. Then add to B a line Z such that B+Z:D=
10 III,  5|      to B a line Z such that B+Z:D=D:B. Then make another
11 III,  5|     line Z such that B+Z:D=D:B. Then make another line
12 III,  5|     having the same ratio to B as KH has to Z, and join
13 III,  5|    as that of Z to KH and of B to KI. If not, let D be
14 III,  5|  ratios to one another as Z, B, and D. But the ratios between
15 III,  5|    But the ratios between Z, B, and D were such that Z+
16 III,  5|       and D were such that Z+B:D=D: B. Therefore IH:IP=
17 III,  5|      were such that Z+B:D=D: B. Therefore IH:IP=IP:IK.
18 III,  5|     the same as that of D to B. Therefore, from the points