Book,  Paragraph

 1   I,  4 |      between movement from C to D and from D to C along that
 2   I,  4 |   movement from C to D and from D to C along that semicircle,
 3   I,  7 | whatever, by in the time C. Let D be less than B; and, assuming
 4   I,  7 |       quantity thus modified by D, E. Then, as D is to B,
 5   I,  7 |      modified by D, E. Then, as D is to B, so is E to some
 6   I,  7 |       of action. In the time C, D will produce that motion
 7   I,  7 |  bearing the same proportion to D as the whole BF bears to
 8   I,  7 |        the movement in the time D. Then, as D is to CD, so
 9   I,  7 |         in the time D. Then, as D is to CD, so is E to some
10   I,  12|   either A or C and either B or D are capable of being present
11   I,  12|       in everything. Then C and D must be predicated of everything
12   I,  12|   between them. In E both C and D must be present, for either
13   I,  12|      the same argument holds of D.~Neither that which always
14   I,  12|       not, C the generated, and D the destructible. Then C
15   I,  12|        and this is true also of D, the destructible. Therefore
16  II,  12|        B to get C, and C to get D, one step or two present