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away 36
axiom 2
az 1
b 107
ba 1
back 14
backward 2
Frequency    [«  »]
113 thus
112 movement
110 too
107 b
107 he
106 impossible
106 man
Aristotle
Physics

IntraText - Concordances

b

    Book, Paragraph
1 I, 2 | must be either (a) one or (b) more than one. If (a) one, 2 I, 2 | principle, others water. If (b) more than one, then either ( 3 I, 2 | continuous is one or that (b) the indivisible is one, 4 I, 2 | also.~But to proceed: If (b) their One is one as indivisible, 5 I, 3 | either of (a) man or of (b) some other subject. But 6 I, 3 | the converse is the case.~(b) If, on the other hand, 7 I, 7 | into existence, and again (b) something which becomes 8 I, 7 | becomes that-the latter (b) in two senses, either the 9 II, 6 | which is for the sake of B, does not result in B. For 10 II, 6 | of B, does not result in B. For instance, taking a 11 III, 3 | acted on and moved, or (b) the agency is in the agent 12 III, 3 | senses.)~Now, in alternative (b), the motion will be in 13 III, 3 | subject, but is of A on B.~(2) There is nothing to 14 III, 5 | of the kind is observed.~(b) Nor can fire or any other 15 III, 5 | not come to rest.~But if (b) the All has dissimilar 16 III, 8 | succession out of existence.~(b) Magnitude is not infinite 17 IV, 2 | generally between predicating B of A because it (A) is itself, 18 IV, 4 | the nail in the ship, or (b) something which is not 19 IV, 8 | then, will move through B in time G, and through D, 20 IV, 8 | time E (if the length of B is egual to D), in proportion 21 IV, 8 | hindering body. For let B be water and D air; then 22 IV, 8 | through D faster than through B. Let the speed have the 23 IV, 8 | the body will traverse B in twice the time that it 24 IV, 8 | void, equal in magnitude to B and to D. Then if A is to 25 IV, 10 | with all things.~Again, (b) change is always faster 26 IV, 11 | them by judging that A and B are different, and that 27 V, 1 | directly causes motion, and (b) on the other hand that 28 V, 6 | these (A) to its contrary (B) has for its opposite remaining 29 V, 6 | its opposite remaining in B. At the same time these 30 VI, 1 | composed of the indivisibles A, B, G, each corresponding part 31 VI, 1 | A when its motion was D, B when its motion was E, and 32 VI, 1 | each of the sections A, B, and G, it follows that 33 VI, 2 | Suppose that A is quicker than B. Now since of two things 34 VI, 2 | has changed from G to D, B will not yet have arrived 35 VI, 2 | which A has arrived at D, B being the slower has arrived, 36 VI, 2 | suppose that A is quicker and B slower, and that the slower 37 VI, 2 | less than GD. And since B, the slower, has passed 38 VI, 4 | time occupied by the motion B. Then if all the time has 39 VI, 5 | that which has changed to B is in something other than 40 VI, 5 | in something other than B, say G, it must again be 41 VI, 5 | again be changing from G to B: for it cannot be assumed 42 VI, 5 | no interval between G and B, since change is continuous. 43 VI, 5 | and let it be divided at B. If then the completion 44 VI, 5 | suppose that it has moved from B to a primary "where" G. 45 VI, 6 | thing has changed from A to B in a moment. Now the moment 46 VI, 6 | case it would be in A and B at once): for we have shown 47 VI, 9 | stationary bodies of equal size, B, B...the bodies, equal in 48 VI, 9 | bodies of equal size, B, B...the bodies, equal in number 49 VI, 9 | number, size, and velocity to B, B....Then three consequences 50 VI, 9 | size, and velocity to B, B....Then three consequences 51 VI, 9 | consequences follow:~First, as the B’s and the G’s pass one another, 52 VI, 9 | pass one another, the first B reaches the last G at the 53 VI, 9 | first G reaches the last B. Secondly at this moment 54 VI, 9 | the A’s, whereas the first B has passed only half the 55 VI, 9 | the same moment all the B’s have passed all the G’ 56 VI, 9 | the first G and the first B will simultaneously reach 57 VI, 9 | G in passing each of the B’s is equal to that occupied 58 VI, 9 | occupied by both the first B and the first G in passing 59 VI, 9 | orbit as described from B or G or any other point 60 VII, 1 | Let A then be moved by B, B by G, G by D, and so 61 VII, 1 | Let A then be moved by B, B by G, G by D, and so on, 62 VII, 1 | respective motions of A, B, G, and each of the other 63 VII, 1 | be the motion of A, Z of B, and H and O respectively 64 VII, 1 | infinite. For the motions of A, B, and the others may be equal, 65 VII, 1 | theoretically possible. If, then, A, B, G, D form an infinite magnitude 66 VII, 4 | the time A the quicker (B) passes over the distance 67 VII, 4 | passes over the distance B’ and the slower (G) passes 68 VII, 4 | passes over the distance G’, B’ will be greater than G’: 69 VII, 4 | be a part of A in which B will pass over a part of 70 VII, 5 | the movement have moved B a distance G in a time D, 71 VII, 5 | A and Z half the weight B: then the ratio between 72 VII, 5 | same time. If, then, A move B a distance G in a time D, 73 VII, 5 | any fraction of it cause B to traverse a part of G 74 VIII, 5 | imparts motion but is unmoved, B something that is moved 75 VIII, 5 | something that is moved by B but moves nothing (granted 76 VIII, 5 | A imparting motion and B being moved, whereas G will 77 VIII, 5 | itself apart from A: for B imparts motion only through 78 VIII, 5 | that imparts motion and B alone that is moved. It 79 VIII, 5 | continuous substance), or from B the part that is moved, 80 VIII, 5 | motion or the remainder of B continue to be moved? If 81 VIII, 8 | indication that motion from A to B is the contrary of motion 82 VIII, 8 | contrary of motion from B to A in the fact that, if 83 VIII, 8 | the motion from A towards B is the contrary of the motion 84 VIII, 8 | locomotion comes to a stand at B and starts again towards 85 VIII, 8 | ceased to be at the point B: it can only have been there 86 VIII, 8 | simultaneously have come to be at B and ceased to be there, 87 VIII, 8 | be in a state of rest at B, and similarly at all other 88 VIII, 8 | in process of locomotion, B, the middle-point, serves 89 VIII, 8 | must come to a stand at B, because it makes it two 90 VIII, 8 | moment when A is at the point B, D is proceeding in uniform 91 VIII, 8 | to be and ceased to be at B: otherwise it will not arrive 92 VIII, 8 | moment when A came to be at B and that at the same moment 93 VIII, 8 | A’s having come to be at B will involve the fact of 94 VIII, 8 | the truth is that A is at B at a sectional point of 95 VIII, 8 | and not-white in the time B. Then D is at the moment 96 VIII, 8 | moment of A, and not-white in B, and G is in both A and 97 VIII, 8 | and G is in both A and B. We must not allow, therefore, 98 VIII, 8 | and that at another time B, a time-atom consecutive 99 VIII, 8 | white and at the moment B it is white, there must 100 VIII, 8 | a becoming between A and B and therefore also a time 101 VIII, 8 | anything: e.g. on arriving at B a thing must also have been 102 VIII, 8 | process of locomotion to B, and that not merely when 103 VIII, 8 | merely when it was near to B, but from the moment of 104 VIII, 10| Let A be the movement, B the moved, and G the infinite 105 VIII, 10| that D moves E, a part of B. Then the time occupied 106 VIII, 10| add to E, I shall use up B: but I shall not use up 107 VIII, 10| A in moving the whole of B, will be finite. Therefore


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