Book, Paragraph

1  VI, 9 |      deal are not divided into halves. The result of the argument
2 VIII, 8|   continuous distance into two halves one point is treated as
3 VIII, 8|        by the act of reckoning halves as well as by the act of
4 VIII, 8|       the act of dividing into halves. But if divisions are made
5 VIII, 8| contains an infinite number of halves, they are not actual but
6 VIII, 8|       not actual but potential halves. If the halves are made
7 VIII, 8|       potential halves. If the halves are made actual, we shall
8 VIII, 8|      the case of reckoning the halves, it is clear that this result
9 VIII, 8|   continuous whole but the two halves. Therefore to the question