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| Alphabetical [« »] created 2 criticized 1 cs 19 d 104 dark 1 dative 1 dealing 3 | Frequency [« »] 110 since 109 good 106 necessarily 104 d 102 cannot 102 similarly 96 again | Aristotle Prior Analytics IntraText - Concordances d |
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1 I, 15| For if C is predicated of D, and D of F, then C is necessarily 2 I, 15| is predicated of D, and D of F, then C is necessarily 3 I, 17| possible for C to belong to all D, it necessarily does not 4 I, 17| does not belong to some D, he would make a false assumption: 5 I, 17| for it does belong to all D, but because in some cases 6 I, 24| C is equal to the angle D, without the additional 7 I, 25| through the propositions C and D, or through the propositions 8 I, 25| inference, e.g. by means of D and E, and again B by means 9 I, 25| the premisses A, B, C, and D. It is necessary then that 10 I, 25| or one or other of C and D, or something other than 11 I, 25| premisses. But if C and D are so related that one 12 I, 25| if C is not so related to D as to make a syllogism, 13 I, 25| conclusion, and if from C and D either A or B follows or 14 I, 25| conclusion follows from C and D, it turns out that these 15 I, 25| of the middle terms C and D, the number of the terms 16 I, 25| e.g. if to ABC the term D is added, two conclusions 17 I, 28| possibly belong to A by D. Suppose again that the 18 I, 28| follows all G. If F and D are identical, A will belong 19 I, 28| and F is identical with D, A will belong to none of 20 I, 28| belonged to none of the Es. If D and G are identical, A will 21 I, 28| because it does not belong to D: but G falls under E: consequently 22 I, 28| will belong to no E, when D and F are identical. Thus 23 I, 28| the middle figure because D belongs to no A, and to 24 I, 28| belong to some E, whenever D and G are identical. This 25 I, 31| be got, be signified by D. The man who divides assumes 26 I, 31| animal, so he assumes A of D as belonging to it. Now 27 I, 31| conclusion is that every D is either B or C, consequently 28 I, 31| footed, C as footless, and D as man, he assumes in the 29 I, 31| footless), and he assumes A of D (for he assumed man, as 30 I, 46| placed under B, and let D stand for not to be not-good’ 31 I, 46| same thing; and either C or D will belong to everything, 32 I, 46| either. On the other hand D belongs to everything to 33 I, 46| belongs. For either C or D belongs to everything to 34 I, 46| simultaneously not-white and white, D must belong to everything 35 I, 46| But A is not true of all D. For of that which is not 36 I, 46| white log. Consequently D is true, but A is not true, 37 I, 46| same thing, and that B and D may possibly belong to the 38 I, 46| equal", C for "unequal", D for "not unequal".~In many 39 I, 46| everything, and again C and D are related in the same 40 I, 46| cannot be reversed, then D must follow B and the relation 41 I, 46| cannot be reversed. And A and D may belong to the same thing, 42 I, 46| following consideration that D follows B. For since either 43 I, 46| B. For since either C or D necessarily belongs to everything; 44 I, 46| thing; it is clear that D must follow B. Again since 45 I, 46| reciprocate with but A, but C or D belongs to everything, it 46 I, 46| it is possible that A and D should belong to the same 47 I, 46| does not reciprocate with D either, since it is possible 48 I, 46| since it is possible that D and A should belong at the 49 I, 46| belong to: and again C and D are related in the same 50 I, 46| necessarily to everything to which D belongs": but this is false. " 51 I, 46| for the negation of C and D. It is necessary then that 52 I, 46| and similarly either H or D, and since H follows F, 53 I, 46| follows F, B must follow D: for we know this. If then 54 I, 46| follows C, B must follow D". But this is false: for 55 I, 46| Similarly also with C and D. For two negations have 56 II, 1 | the predicate A: for if D is included in B as in a 57 II, 1 | B is included in A, then D will be included in A. Again 58 II, 1 | belongs to no C. If then D is subordinate to C, clearly 59 II, 11| or that B belongs to all D; thus we get the first figure. 60 II, 11| B, and B belongs to all D, A belongs to no D. Let 61 II, 11| to all D, A belongs to no D. Let this be impossible: 62 II, 17| belongs to B, B to C, and C to D, and it should be false 63 II, 17| false that B belongs to D: for if we eliminated A 64 II, 17| B belongs to C and C to D, the false conclusion would 65 II, 17| that A should belong to D, the false conclusion will 66 II, 17| K belongs to C and C to D, the impossible conclusion 67 II, 18| and B, and these through D, E, F, and G, one of these 68 II, 18| are inferred by means of D, E, F, and G. Therefore 69 II, 19| inferred to be true of F, B, C, D, and E being middle terms. 70 II, 19| belongs to B, and next whether D belongs to E, instead of 71 II, 21| that B and C belong to all D in the same way. If then 72 II, 21| belongs to all B, and B to D, but A to no C, and C to 73 II, 21| A to no C, and C to all D, he will both know and not 74 II, 21| belongs to B, B to C, and C to D, but some one thinks that 75 II, 21| both know that A belongs to D, and think that it does 76 II, 21| both B and C belong to all D. For it turns out that the 77 II, 21| knows that B belongs to D, then he knows that A belongs 78 II, 21| knows that A belongs to D. Consequently if again he 79 II, 21| belongs to all B, and B to D, and again A belongs to 80 II, 22| convertible, and similarly C and D, and if A or C must belong 81 II, 22| anything whatever, then B and D will be such that one or 82 II, 22| to which A belongs, and D belongs to that to which 83 II, 22| together, it is clear that B or D belongs to everything, but 84 II, 22| to everything and if C or D belongs to everything, but 85 II, 22| C are convertible B and D are convertible. For if 86 II, 22| belong to something to which D belongs, it is clear that 87 II, 22| convertible. Therefore C and D belong together. But this 88 II, 22| preferable to B, and similarly D is preferable to C, then 89 II, 22| are preferable to B and D together, A must be preferable 90 II, 22| A must be preferable to D. For A is an object of desire 91 II, 22| is similarly related to D, since they also are opposites. 92 II, 22| desire to the same extent as D, B is an object of aversion 93 II, 22| and C together, and B and D together, will be equally 94 II, 22| are preferable to B and D, A cannot be equally desirable 95 II, 22| be equally desirable with D; for then B along with D 96 II, 22| D; for then B along with D would be equally desirable 97 II, 22| with A along with C. But if D is preferable to A, then 98 II, 22| A then is preferable to D, and C consequently is less 99 II, 22| the favour (represented by D) without being such as to 100 II, 24| Athenians against Thebans, D Thebans against Phocians. 101 II, 24| that B belongs to C and to D (for both are cases of making 102 II, 24| neighbours) and that A belongs to D (for the war against the 103 II, 24| B will be proved through D. Similarly if the belief 104 II, 25| knowledge. For example let D stand for squaring, E for