Book, Paragraph

 1      I, 5|    predicated of no N, but of all O. Since, then, the negative
 2      I, 5|          assumed to belong to all O: consequently N will belong
 3      I, 5|  consequently N will belong to no O. This has already been proved.
 4      I, 5|       belongs to all N, but to no O, then N will belong to no
 5      I, 5|          then N will belong to no O. For if M belongs to no
 6      I, 5|            For if M belongs to no O, O belongs to no M: but
 7      I, 5|         For if M belongs to no O, O belongs to no M: but M (
 8      I, 5|           said) belongs to all N: O then will belong to no N:
 9      I, 5|  convertible, N will belong to no O. Thus it will be the same
10      I, 5|         predicated of every N and O, there cannot be a syllogism.
11      I, 5|       neither of any N nor of any O. Terms to illustrate a positive
12      I, 5|      belongs to no N, but to some O, it is necessary that N
13      I, 5|           does not belong to some O. For since the negative
14      I, 5|        admitted to belong to some O: therefore N will not belong
15      I, 5|           will not belong to some O: for the result is reached
16      I, 5|         to all N, but not to some O, it is necessary that N
17      I, 5|           does not belong to some O: for if N belongs to all
18      I, 5|           for if N belongs to all O, and M is predicated also
19      I, 5|           N, M must belong to all O: but we assumed that M does
20      I, 5|           does not belong to some O. And if M belongs to all
21      I, 5|           to all N but not to all O, we shall conclude that
22      I, 5|          N does not belong to all O: the proof is the same as
23      I, 5|         if M is predicated of all O, but not of all N, there
24      I, 5|        when M is predicated of no O, but of some N. Terms to
25      I, 5|          to no N, and not to some O. It is possible then for
26      I, 5|           to belong either to all O or to no O. Terms to illustrate
27      I, 5|          either to all O or to no O. Terms to illustrate the
28      I, 5| universally, if M belongs to some O, and does not belong to
29      I, 5|           does not belong to some O. For if N belonged to all
30      I, 5|          For if N belonged to all O, but M to no N, then M would
31      I, 5|         then M would belong to no O: but we assumed that it
32      I, 5|           that it belongs to some O. In this way then it is
33      I, 5|           does not belong to some O, even if it belongs to no
34      I, 5|          even if it belongs to no O, and since if it belongs
35      I, 5|         since if it belongs to no O a syllogism is (as we have
36      I, 5|       belong to all N and to some O. It is possible then for
37      I, 5|       then for N to belong to all O or to no O. Terms to illustrate
38      I, 5|          belong to all O or to no O. Terms to illustrate the
39      I, 5|    universal, and M belongs to no O, and not to some N, it is
40      I, 5|           to belong either to all O or to no O. Terms for the
41      I, 5|          either to all O or to no O. Terms for the positive
42     II, 8|         the conclusion reached by O, conversion lacks universality,