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| Alphabetical [« »] musical 7 must 250 my 1 n 31 name 1 namely 1 natural 8 | Frequency [« »] 32 would 31 ac 31 belonging 31 n 31 predicate 31 were 31 without | Aristotle Prior Analytics IntraText - Concordances n |
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1 I, 5| Let M be predicated of no N, but of all O. Since, then, 2 I, 5| relation is convertible, N will belong to no M: but 3 I, 5| belong to all O: consequently N will belong to no O. This 4 I, 5| Again if M belongs to all N, but to no O, then N will 5 I, 5| all N, but to no O, then N will belong to no O. For 6 I, 5| was said) belongs to all N: O then will belong to no 7 I, 5| O then will belong to no N: for the first figure has 8 I, 5| relation is convertible, N will belong to no O. Thus 9 I, 5| M is predicated of every N and O, there cannot be a 10 I, 5| predicated neither of any N nor of any O. Terms to illustrate 11 I, 5| For if M belongs to no N, but to some O, it is necessary 12 I, 5| O, it is necessary that N does not belong to some 13 I, 5| statement is convertible, N will belong to no M: but 14 I, 5| belong to some O: therefore N will not belong to some 15 I, 5| Again if M belongs to all N, but not to some O, it is 16 I, 5| O, it is necessary that N does not belong to some 17 I, 5| belong to some O: for if N belongs to all O, and M 18 I, 5| is predicated also of all N, M must belong to all O: 19 I, 5| And if M belongs to all N but not to all O, we shall 20 I, 5| we shall conclude that N does not belong to all O: 21 I, 5| of all O, but not of all N, there will be no syllogism. 22 I, 5| predicated of no O, but of some N. Terms to illustrate a positive 23 I, 5| e.g. let M belong to no N, and not to some O. It is 24 I, 5| It is possible then for N to belong either to all 25 I, 5| belong to some O. For if N belonged to all O, but M 26 I, 5| belonged to all O, but M to no N, then M would belong to 27 I, 5| e.g. let M belong to all N and to some O. It is possible 28 I, 5| It is possible then for N to belong to all O or to 29 I, 5| to no O, and not to some N, it is possible for N to 30 I, 5| some N, it is possible for N to belong either to all 31 I, 6| should one of the Ss, e.g. N, be taken, both P and R